when the denominator of. 3/ root 5 + root 2
is rationalised it gives
Please show the steps also
And no spam and misuse the forum / if don't know the answer then don't do it or I will report that user
is rationalised it gives
Please show the steps also
And no spam and misuse the forum / if don't know the answer then don't do it or I will report that user
Add an Answer
More Questions From This User See All
Answers & Comments
Verified answer
Answer:
I THINK IT'S HELPFULLY FOR YOU TO
MARK AS BRILLIANT
Answer:
[tex]\sqrt{5} - \sqrt{2}[/tex]
Step-by-step explanation:
[tex]= \frac{3}{\sqrt{5} + \sqrt{2} }[/tex]
To rationalize, multiply the additive inverse of the denominator with both the numerator and the denominator
[tex]= \frac{3}{\sqrt{5} + \sqrt{2} }[/tex] × [tex]\frac{\sqrt{5} - \sqrt{2} }{\sqrt{5} - \sqrt{2} }[/tex]
= [tex]\frac{3(\sqrt{5} - \sqrt{2}) }{(\sqrt{5}) ^{2} - (\sqrt{2}) ^{2} }[/tex] [ (a+b) (a-b) = [tex]a^{2} - b^{2}[/tex]]
= [tex]\frac{3(\sqrt{5} - \sqrt{2}) }{5 - 2}[/tex]
= [tex]\frac{3(\sqrt{5} - \sqrt{2}) }{3}[/tex]
= [tex]\sqrt{5} - \sqrt{2}[/tex]