Answer:

Given, both vectors have same magnitude i.e., ∣a∣=∣b∣ and scalar product of vectors, a⋅b=

2

1

(given).

Let θ be the angle between two vectors a and b. Then,

cosθ=

∣a∣∣b∣

a⋅b

⇒cos60

∘

=

∣a∣∣a∣

2

1

[∵∣a∣=∣b∣(given)]

⇒

2

1

=

2∣a∣

2

1

⇒∣a∣=1

∴∣a∣=∣a∣=1.

HOPE IT HELPS PLEASE MARK AS BRAINLIEST

Answer:

Given, both vectors have same magnitude i.e., ∣a∣=∣b∣ and scalar product of vectors, a⋅b=

2

1

(given).

Let θ be the angle between two vectors a and b. Then,

cosθ=

∣a∣∣b∣

a⋅b

⇒cos60

∘

=

∣a∣∣a∣

2

1

[∵∣a∣=∣b∣(given)]

⇒

2

1

=

2∣a∣

2

1

⇒∣a∣=1

∴∣a∣=∣a∣=1

I hope fully answer