A train is travelling at a speed of 25m/s. Brakes are applied so as to produce a uniform acceleration of -0.5m/s. Find how far the train will go before it is brought to rest.
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Answer:
25m
Explanation:
initial velocity (u) = 25m/s
final velocity (f) = 0m/s
acceleration (a) = -0.5m/s
displacement (s) = s
Then,
v² = u²+2*a*s
0² = 25 + 2*(-0.5)*s
0² = 25 + (-s)
0 = 25 - s
s = 25 + 0
s = 25m
Answer:
625mtrs
Explanation:
v²=u²+2as
here v=0 and acceleration is -ve then it becomes 2as=u²
s=u²/2a
s=25²÷(2×0.5)
s=625mtr