If 2x-1 is an odd number and 3y-1 is an even number, which of the following is are
necessarily even?
(I) x2 – 2y + 2
(II) y2 - 2x + 3
(III) 4x2 - y - 1
a) I only
b) II only
c) I and II
d) II and III
necessarily even?
(I) x2 – 2y + 2
(II) y2 - 2x + 3
(III) 4x2 - y - 1
a) I only
b) II only
c) I and II
d) II and III
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Answers & Comments
x2-2y+2 can be the only possible.
so, the answer is a) 1only