F∝1d2,given F′=64F100F,d′=(d+3) ∴FF′=(d+3)2d2 ⇒64F100F=d2(d+3)3⇒810=dd+3 8d+24=10d 2d=24⇒d=12m
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F∝1d2,given F′=64F100F,d′=(d+3) ∴FF′=(d+3)2d2 ⇒64F100F=d2(d+3)3⇒810=dd+3 8d+24=10d 2d=24⇒d=12m