N₂ + 3H₂ → 2NH₃
For N₂
molar mass of N₂ = 14.01 g/mol × 2
molar mass of N₂ = 28.02 g/mol
For H₂
molar mass of H₂ = 1.008 g/mol × 2
molar mass of H₂ = 2.016 g/mol
Using N₂
mole ratio = 1 mol N₂ : 2 mol NH₃
Using H₂
mole ratio = 3 mol H₂ : 2 mol NH₃
moles of NH₃ = 1.02 mol
moles of NH₃ = 1.39 mol
Since N₂ produces less number of moles of NH₃,
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Answers & Comments
Step 1: Write the balanced chemical equation.
N₂ + 3H₂ → 2NH₃
Step 2: Calculate the molar mass of each reactant.
For N₂
molar mass of N₂ = 14.01 g/mol × 2
molar mass of N₂ = 28.02 g/mol
For H₂
molar mass of H₂ = 1.008 g/mol × 2
molar mass of H₂ = 2.016 g/mol
Step 3: Determine the mole ratios needed.
Using N₂
mole ratio = 1 mol N₂ : 2 mol NH₃
Using H₂
mole ratio = 3 mol H₂ : 2 mol NH₃
Step 4: Calculate the number of moles of NH₃ produced by each reactant.
Using N₂
moles of NH₃ = 1.02 mol
Using H₂
moles of NH₃ = 1.39 mol
Step 5: Determine the limiting reactant.
Since N₂ produces less number of moles of NH₃,