3. The angle of elevation of a jet fighter from point A on ground is 60°. After flying 10 seconds, the angle changes
to 30°. If the jet is flying at a speed of 648 km/hour, find the constant height at which the jet is flying.
PLS I NEED STEP BY STEP EXPLANATION.......
to 30°. If the jet is flying at a speed of 648 km/hour, find the constant height at which the jet is flying.
PLS I NEED STEP BY STEP EXPLANATION.......
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Step-by-step explanation:
flight is just a flying at a speed of 648 km per hour
= 648000/3600 m/s
= 180 m/s
Distance covered in 10 secs = 180 * 10 = 1800 m
Height at which flying = H m
H/Tan30 - H/Tan60 = 1800
=> H√3 - H/√3 = 1800
=> 3H - H = 1800√3
=> 2H = 1800√3
=> H = 900√3 = 1,558.8 m
the constant height at which the Jets flying = 900√3= 1558.8m
Answer:
h = 15.5 m
Step-by-step explanation:
[speed = 648 km/h
speed = 648 km/htime = 10s
speed = 648 km/htime = 10s speed = distance/time
speed = 648 km/htime = 10s speed = distance/time648 = d/ 10
speed = 648 km/htime = 10s speed = distance/time648 = d/ 10d = 6480km]
this is just an extra info
*rest is given in the attached pic