Answer:

HEY MATE !!!!!!!!

Step-by-step explanation:

STEPS OF CONSTRUCTION:

1. Draw a line segment BC =7cm.

2. At B draw ∠CBY = 60° and cut off BA =6 cm from it.

3. Join AC. Thus ∆ABC is a given Triangle.

4. Now from B draw a ray BX making an acute ∠CBX  on the side opposite to the vertex A.

5. Mark 4 points B1,B2,B3,B4 on BX such that BB1 = B1B2 = B2B3 = B3B4.

6.Join B4C and from B3 draw B3C’ || B4C intersecting BC at C’.

7. From point C’ draw C’A’ || CA intersecting AB at A’. Thus , ∆A’B’C’  is the required triangle whose sides are 3/4 of the corresponding sides of ∆ABC.

HOPE IT'S HELPFUL :)

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