Hiii friends...!✌I need urgent help... I've an exam today...Please answer the following questions with proper and complete explanations. NO COPYING AND NO IRRELEVANT ANSWERS REQUIRED.1. The resistance of a wire is 20 ohm. It is so stretched that the length becomes three times, then the new resistance of the wire is?..Sorry to say but now I realized that this app is of no help...;((..Open my profile and see the latest questions...And solve if you can...PLEASE. Created by TheAstrophile. Physics

R=(ρ∗L)/AR=(ρ∗L)/AIf the wire is an isolated system (no extra metals/wires coming in or going out) with a specified length and cross-sectional area, then stretching it would increase the length 3 times and presumably reduce the cross-sectional area 3 times as well. Then,R=(ρ∗3L)/(1/3∗A)R=(ρ∗3L)/(1/3∗A)R=9(ρ∗L)/A)R=9(ρ∗L)/A)You get 9 times more resistance you initially had, this makes sense as you bring the wire to a thinner cross-sectional area, the electrons have more material to go through.Thankshope you like itplease mark as a brainliest answer^_^