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Sanjana111111
@Sanjana111111
June 2022
1
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Heyy guys plzzz answer this ques 13 it's urgent.....
Answers & Comments
rohitkumargupta
Verified answer
Hello dear,
let QS=x
QS=ST=TR=X
QT=2X
QR=3X
,in TRIANGLE PQT,. angleQ=90
PT²=PQ²+QT²
PQ²+4X²-----------------(1)
in trianglePQR, ANGLE Q=90
PR²=PQ²+QR²
PQ²+9X²-----------------(2)
in trianglePQS, angle Q=90
PS²=PQ²+QS²
PQ²+X²
from equation (1)
8PT²=8PQ²+32X²------------(3)
[now, multiply equation (1)by 8]
3PR²+5PS²=3(PQ²+9X²)+5(PQ²+X²)
=3PQ²+27X²+5PQ²+5X²
=8PQ²+32X²
=8(PQ+4X²)
=8PT². [FROM 2
1 votes
Thanks 5
Sanjana111111
tysm
rohitkumargupta
means
rohitkumargupta
ooohk
rohitkumargupta
welcome
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Answers & Comments
Verified answer
Hello dear,let QS=x
QS=ST=TR=X
QT=2X
QR=3X
,in TRIANGLE PQT,. angleQ=90
PT²=PQ²+QT²
PQ²+4X²-----------------(1)
in trianglePQR, ANGLE Q=90
PR²=PQ²+QR²
PQ²+9X²-----------------(2)
in trianglePQS, angle Q=90
PS²=PQ²+QS²
PQ²+X²
from equation (1)
8PT²=8PQ²+32X²------------(3)
[now, multiply equation (1)by 8]
3PR²+5PS²=3(PQ²+9X²)+5(PQ²+X²)
=3PQ²+27X²+5PQ²+5X²
=8PQ²+32X²
=8(PQ+4X²)
=8PT². [FROM 2