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Sanjana111111
@Sanjana111111
July 2022
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the centre of a circle is (2 p - 1, 2p - 2 )if a circle passes through the point A (1,2) and the length of its diameter is 20 units find p.
Answers & Comments
rohitkumargupta
Verified answer
HELLO DEAR,
GIVEN THAT:-
Diameter :- 20 units .
Radius :- 10 units .
A ( 1 , 2 ) , O ( 2p - 1 , 2p - 2 ) .
AO = 10 units .
To find :- p = ?
Solution ;-
By distance formula :-
Squaring on both sides ;-
8p2 - 24p + 20 = 100
8p2 - 24p + 20 - 100 = 0
8p2 - 24p - 80 = 0
p2 - 3p - 10 = 0
By using quadratic formula
Let p = x .
THEN ,
X²- 5X + 2X - 10
=> X(X-5) +2(X-5)
(X+2) (X-5)=0
THEN X=5 &X=-2
I HOPE ITS HELP YOU DEAR,
THANKS
38 votes
Thanks 79
hemantvats17
Diameter :- 20 units .
Radius :- 10 units .
A ( 1 , 2 ) , O ( 2p - 1 , 2p - 2 ) .
AO = 10 units .
To find :- p = ?
Solution ;-
By distance formula :-
Squaring on both sides ;-
8p2 - 24p + 20 = 100
8p2 - 24p + 20 - 100 = 0
8p2 - 24p - 80 = 0
p2 - 3p - 10 = 0
By using quadratic formula
Let p = x .
THEN ,
X²- 5X + 2X - 10
=> X(X-5) +2(X-5)
(X+2) (X-5)=0
THEN X=5 &X=-2√
15 votes
Thanks 25
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Answers & Comments
Verified answer
HELLO DEAR,GIVEN THAT:-
Diameter :- 20 units .
Radius :- 10 units .
A ( 1 , 2 ) , O ( 2p - 1 , 2p - 2 ) .
AO = 10 units .
To find :- p = ?
Solution ;-
By distance formula :-
Squaring on both sides ;-
8p2 - 24p + 20 = 100
8p2 - 24p + 20 - 100 = 0
8p2 - 24p - 80 = 0
p2 - 3p - 10 = 0
By using quadratic formula
Let p = x .
THEN ,
X²- 5X + 2X - 10
=> X(X-5) +2(X-5)
(X+2) (X-5)=0
THEN X=5 &X=-2
I HOPE ITS HELP YOU DEAR,
THANKS
Radius :- 10 units .
A ( 1 , 2 ) , O ( 2p - 1 , 2p - 2 ) .
AO = 10 units .
To find :- p = ?
Solution ;-
By distance formula :-
Squaring on both sides ;-
8p2 - 24p + 20 = 100
8p2 - 24p + 20 - 100 = 0
8p2 - 24p - 80 = 0
p2 - 3p - 10 = 0
By using quadratic formula
Let p = x .
THEN ,
X²- 5X + 2X - 10
=> X(X-5) +2(X-5)
(X+2) (X-5)=0
THEN X=5 &X=-2√