Step-by-step explanation:
(20x+ 3) (20x-5)
By using identity (x+a) (x+b)= x²+(a+b)x+ab
(20x+3) (20x-5)= (20x)²+(3-5)20x+3×(-5)
= 400x²+(-2)20x-15
= 400x²-40x-15. ( Factor of 5 )
= 80x²-8x-3
Answer:
Let us assume it as,
Where, x = 20x
a = 3
b = 5
We know that,
∴
=
Hope it helps you^_^
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Answers & Comments
Step-by-step explanation:
(20x+ 3) (20x-5)
By using identity (x+a) (x+b)= x²+(a+b)x+ab
(20x+3) (20x-5)= (20x)²+(3-5)20x+3×(-5)
= 400x²+(-2)20x-15
= 400x²-40x-15. ( Factor of 5 )
= 80x²-8x-3
Answer:
Let us assume it as,
Where, x = 20x
a = 3
b = 5
We know that,
∴![(20x + 3) (20x -5 )= (20x)^2 + (3 - 5)20x - (3 * 5) (20x + 3) (20x -5 )= (20x)^2 + (3 - 5)20x - (3 * 5)](https://tex.z-dn.net/?f=%2820x%20%2B%203%29%20%2820x%20-5%20%29%3D%20%2820x%29%5E2%20%2B%20%283%20-%205%2920x%20-%20%283%20%2A%205%29)
=![400x^2 - 40x - 15 400x^2 - 40x - 15](https://tex.z-dn.net/?f=400x%5E2%20-%2040x%20-%2015)
=![5(80x^2 - 8x - 3) 5(80x^2 - 8x - 3)](https://tex.z-dn.net/?f=5%2880x%5E2%20-%208x%20%20-%203%29)
Hope it helps you^_^