Step-by-step explanation:
semi peri.= (a+b+c)/2
s = (8+10+10)/2
s = 28/2
s = 14
area of ∆= √s(s-a)(s-b)(s-c)
= √14(14-8)(14-10)(14-10)
= √14×6×4×4
= √2×7×2×3×4×4
=4×2√7×3
= 8√21
rate of 1cm²= 120
rate of 8√21 trangular plot= 120×8√21
rate of trangular plot= 960√21
Q)area of base =πr²=192
area of cylinder= πr²h
= 192×h
= 192×10
= 1920
#666
Semi-perimeter (S) =
S =
Hence, Cost of the plot = 8√21 × 120 = 960√21 Rs.
In the question we are already provided with the base area = 192cm² = 2πr
hence, 1920 cm³ is the required answer
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Answers & Comments
Step-by-step explanation:
semi peri.= (a+b+c)/2
s = (8+10+10)/2
s = 28/2
s = 14
area of ∆= √s(s-a)(s-b)(s-c)
= √14(14-8)(14-10)(14-10)
= √14×6×4×4
= √2×7×2×3×4×4
=4×2√7×3
= 8√21
rate of 1cm²= 120
rate of 8√21 trangular plot= 120×8√21
rate of trangular plot= 960√21
Q)area of base =πr²=192
area of cylinder= πr²h
= 192×h
= 192×10
= 1920
#666
1.] Correct Question:-
Given:-
To find:-
Formula to be used:-
Solution:-
Semi-perimeter (S) =
S =
S =
Hence, Cost of the plot = 8√21 × 120 = 960√21 Rs.
2.] Correct Question:-
Given:-
To find:-
Formula:-
In the question we are already provided with the base area = 192cm² = 2πr
Solution:-
hence, 1920 cm³ is the required answer