Answer:
Step-by-step explanation:
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Length of Wire is 112000 cm
Given: OQ = QP, H = 10 cm and OP = 20 cm
∠DOC = 60° and ∠DOP = 30°
Radius of wire, r =
To find: Length of wire, h
Let radius of frustum are
In ΔPOD,
In ΔQOB,
Volume of wire = volume of frustum
Therefore, Length of Wire is 112000 cm
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Answer:
Step-by-step explanation:
Here is your answer
Plz mark it brainiest as i need it
Answer:
Length of Wire is 112000 cm
Step-by-step explanation:
Given: OQ = QP, H = 10 cm and OP = 20 cm
∠DOC = 60° and ∠DOP = 30°
Radius of wire, r =![\frac{1}{12}\:cm \frac{1}{12}\:cm](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B12%7D%5C%3Acm)
To find: Length of wire, h
Let radius of frustum are![r_1=PD\,,\,r_2=QB r_1=PD\,,\,r_2=QB](https://tex.z-dn.net/?f=r_1%3DPD%5C%2C%2C%5C%2Cr_2%3DQB)
In ΔPOD,
In ΔQOB,
Volume of wire = volume of frustum
Therefore, Length of Wire is 112000 cm