radius=10cm=10/100 =1/10 in meter
length of water flowing through the pipe in 1 hour = 3km =3000m
volume of water that flows to the pipe in 1 hour = pie r^2 = (pie ×(1/10)^2 ×3000) m^3 =30 pie
radius of the cylindrical tank=5m
dep=2 m
pie ×5^2×2=50
time taken = volume of tank / volume of water flown in 1 hour
50pie÷30pie=5/3 hrs
i e 1hr 40 min
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
= π( 10/ 2)^2 × 2 m^3
= 50πm^3
Now , let the time taken by the pipe to fill the tank be x hr.
Now , 4km / h = 4000m
In case of pipe,
D =20cm
→R=1/10 m
Volume of water flowed from tank in one hour = πR^2h
=π×1/100×4000 m^3
Thus , required time =x
= 50π×100/4000π
= 5/4 hr
=1.25 hr
The required answer is 1.25 hr or 1hr15min
radius=10cm=10/100 =1/10 in meter
length of water flowing through the pipe in 1 hour = 3km =3000m
volume of water that flows to the pipe in 1 hour = pie r^2 = (pie ×(1/10)^2 ×3000) m^3 =30 pie
radius of the cylindrical tank=5m
dep=2 m
pie ×5^2×2=50
time taken = volume of tank / volume of water flown in 1 hour
50pie÷30pie=5/3 hrs
i e 1hr 40 min