mathshater
To factorise we first find the multiplication of coefficient of x*2 and constant term and then try to express coefficient of x in the form of a addition of the factors of the number got after mutiplication
x^2+2root2-6 multiplication of the terms=-6 expressing as the sum of factors =3root2-root2 x^2+3root2x-root2x-6 taking x common in first two terms and -root2 common in the last two terms x (x+3root2)-root2 (x+3root2) taking (x+3root2)common (x+3root2)(x-root2)
for finding roots of x put it equal to 0
(x+3root2)(x-root2)=0
now two cases arise case-1 (x+3root2)=0 x=-3root2 case-2 (x-root2)=0 x=root2
hope it helps ............... comment for any doubt asking question does not show someone's weakness it is a matter of excellence
pls mark as best..............
1 votes Thanks 2
mathshater
Won't u mark it best I think it's better than of the other guy
Answers & Comments
x(x+3√2)-√2(x+3√2)
(x-√2)(x+3√2)
The zeroes are √2 and -3√2 ok now Mark it
x^2+2root2-6
multiplication of the terms=-6
expressing as the sum of factors =3root2-root2
x^2+3root2x-root2x-6
taking x common in first two terms and
-root2 common in the last two terms
x (x+3root2)-root2 (x+3root2)
taking (x+3root2)common
(x+3root2)(x-root2)
for finding roots of x put it equal to 0
(x+3root2)(x-root2)=0
now two cases arise
case-1
(x+3root2)=0
x=-3root2
case-2
(x-root2)=0
x=root2
hope it helps ...............
comment for any doubt
asking question does not show someone's weakness it is a matter of excellence
pls mark as best..............