Prove that (p)^1/n is irrational, when p is prime and n > 1.
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kartik179
The proof that, under this condition, x is irrational will be done indirectly by assuming that x is rational, then showing that this assumption leads to a contradiction.
Let x be rational; i.e., let x = a/b where a and b are integers. Then:
p = xn = an/bn = a rational number.
Since p is prime, then p is an integer. Thus, either:
bn = 1 or bn = am where m < n
1) If bn = 1, then p = an, and p has factors other than p and 1,13 violating the assumption that p is prime. Therefore, bn ≠1.
2) If bn = am, where m < n, then p = am+1… an, and p still has factors other than p and 1,14 violating the assumption that p is prime.
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kartik179
can u give my answer as the brainliest answer
Answers & Comments
Let x be rational; i.e., let x = a/b where a and b are integers. Then:
p = xn = an/bn = a rational number.
Since p is prime, then p is an integer. Thus, either:
bn = 1 or bn = am where m < n
1) If bn = 1, then p = an, and p has factors other than p and 1,13 violating the assumption that p is prime. Therefore, bn ≠1.
2) If bn = am, where m < n, then p = am+1… an, and p still has factors other than p and 1,14 violating the assumption that p is prime.
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