[tex] \sf(x-8)(x-2-i)(x-2+i)=
[tex] \sf \: (x-8)(x²-4x+4+1)=
[tex] \sf \: (x-8)(x²-4x+5)=
[tex] \sf \: x³-4x²+5x =
[tex] \sf \: -8x²+32x-40=
[tex] \sf \: x³-12x²+37x-40
\sf \: is \: a polynomial \: of \: least \: degree \: with \: a \: leading \: coefficient \: of \: 1.
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Answers & Comments
[tex] \sf(x-8)(x-2-i)(x-2+i)=
[tex] \sf \: (x-8)(x²-4x+4+1)=
[tex] \sf \: (x-8)(x²-4x+5)=
[tex] \sf \: x³-4x²+5x =
[tex] \sf \: -8x²+32x-40=
[tex] \sf \: x³-12x²+37x-40
\sf \: is \: a polynomial \: of \: least \: degree \: with \: a \: leading \: coefficient \: of \: 1.
Pede po ba kahit walang sol?