Verified answer

★ Cumulative frequency table refer to attachment ★

To find :-

• Median of given data

Solution :-

As we know that

→ Median = l + {h × (N/2 - cf/f)}

Where

• l = lower limit
• h = width of median class
• cf = cumulative frequency
• N = Σf

Now, according to given condition

→ N = Σf

→ N = 50

→ N/2 = 50/2 = 25

Cumulative frequency i.e greater than 25 is 36

∴ Median Class = 60 - 80

• l = 60
• h = 20
• f = 12
• c.f (preceding class) = 24

→ Me = l + {h × (N/2 - cf/f)}

Substitute all the values

→ Me = 60 + {20 × (25 - 24)/12}

→ Me = 60 + {20 × 1/12}

→ Me = 60 + 20/12

→ Me = 60 + 5/3

→ Me = 60 + 1.66

→ Me = 61.66

Hence,

• Median of given data is 61.66

Note :

• Me denotes Median
• Σ → Sigma → Summation