A boat is moving due east in a region where the earth's magnetic field is 5.0×10⁻⁵ NA⁻¹ m⁻¹ due north and horizontal. The boat carries a vertical aerial 2 m long. If the speed of the boat is 1.50 ms⁻¹ , the magnitude of the induced emf in the wire of aerial is:
Answers & Comments
Or,
Here,
We use speed = Distance/time. We get:
EMF = Magnetic flux density x Width x Speed.
Substitute in formula. Do check if the units are the same.
➥ EMF = 5.0 × 10⁻⁵ NA⁻¹ m⁻¹ × 2 m × 1.5 m/s
➥ EMF = 15 × 10⁻⁵ Volts.
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