find the area of a triangle, two sides of which are 8cm and 11cm and the perimet...

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find the area of a triangle, two sides of which are 8cm and 11cm and the perimeter is 32 cm..
answerrrrrr please
thanks lots of heartssss

adityakute1817 Given,

peimeter=32 cm.

sides=8,11

=sum of both sides - perimetre

32-8+11

32-19=13

sides=8 cm., 11 cm., 13 cm.

semi perimeter =a+ b+ c / 2

= 8+11+13 /2

32/2

so, s=16 cm.

area of a triangle = [root under] s(s-a) (s-b) (s-c)

s-a=16-8=8

s-b=16-11=5

s-c=16-13=3

[root under] 16 x 8 x 5 x 3

[root under] 2 x 8 x 8 x 5 x 3

=8 [root under] 30

navyarajiv thanks

np200323 AREA OF THE TRIANGLE=1/2 INTO B INTO H
=1/2 INTO 8 INTO 11
=4 INTO 11
AREA OF THE TRIANGLE=44CM^2

navyarajiv thanks

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