1) find the area of a triangular whose sides are 40m, 90m and 70m.
2) FInd the cost of leveling aground in the form of a triangle with sides 16m, 12m and 20m at rs. 4 per sq. meter.
PLEASE ANSWER THIS 2 QUESTIONS FAST
THANKS LOTS OF LOVEEE
2) FInd the cost of leveling aground in the form of a triangle with sides 16m, 12m and 20m at rs. 4 per sq. meter.
PLEASE ANSWER THIS 2 QUESTIONS FAST
THANKS LOTS OF LOVEEE
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Area of triangle = √{s(s-a)(s-b)(s-c)}
where, s = (a+b+c)/2 where a,b,c are sides.
So, s = (40+90+70)/2 =100m
By putting the given values ,
Area = √{100(100-40)(100-90)(100-70)}
= √(100*60*10*30) = √(180000) = 300√2 m^2.
2) Again , we apply Heron's formula ,
Area of triangle = √{s(s-a)(s-b)(s-c)}
where, s = (a+b+c)/2 where a,b,c are sides.
So, s = (16+12+20)/2 =24 m
By putting the given values ,
Area = √{24*(24-16)(24-12)(24-20)}
= √ { 24* 8*12*4}
= 96 m^2.
So, cost of leveling at the rate of 4 per sq.m is
Rs 4 *96 = Rs 384.
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