Given Quadratic Equation → x² - 10x + 9
For factorising a polynomial of second degree, there are 3 methods which can be followed
Here we apply the first method which is splitting of middle term.
For this find 2 numbers such that:
Those 2 numbers which fulfill the above requirement are -9 and -1
So, the given Quadratic equation can be written as:
x² - x - 9x + 9 = 0
⇒ x(x - 1) - 9(x - 1) = 0
⇒ (x - 9) (x - 1) = 0
So, the factors are:
Answer:
for solution refer the attachment
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Given Quadratic Equation → x² - 10x + 9
For factorising a polynomial of second degree, there are 3 methods which can be followed
Here we apply the first method which is splitting of middle term.
For this find 2 numbers such that:
Those 2 numbers which fulfill the above requirement are -9 and -1
So, the given Quadratic equation can be written as:
x² - x - 9x + 9 = 0
⇒ x(x - 1) - 9(x - 1) = 0
⇒ (x - 9) (x - 1) = 0
So, the factors are:
Verified answer
Answer:
for solution refer the attachment
please mark it as brainliest and
thank if it helps you