Answer:
lo ur a s
Step-by-step explanation:
Let ABC be a right angled triangle with right angle at B
let AB=5x and BC=3x−1.
Then, area =△ABC=
2
1
(Base×Height))
⇒60=
(AB×BC)⇒60=
×5x(3x−1)
⇒120=5x(3x−1)⇒3x
−x−24=0⇒3x
−9x+8x−24=0
⇒(x−3)(3x+8)=0⇒x=3or3x+8=0⇒x=3orx=−
3
8
⇒x=3
AB=5x=5×3=15cm and BC=(3x−1)=(3×3−1)=8cm
Now, AC
+AB
+BC
⇒AC
=15
+8
=289⇒AC=17cm
Hence, hypotenuse =17cm
hi
i am searching for that so I don't know
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Answers & Comments
Answer:
lo ur a s
Step-by-step explanation:
Let ABC be a right angled triangle with right angle at B
let AB=5x and BC=3x−1.
Then, area =△ABC=
2
1
(Base×Height))
⇒60=
2
1
(AB×BC)⇒60=
2
1
×5x(3x−1)
⇒120=5x(3x−1)⇒3x
2
−x−24=0⇒3x
2
−9x+8x−24=0
⇒(x−3)(3x+8)=0⇒x=3or3x+8=0⇒x=3orx=−
3
8
⇒x=3
AB=5x=5×3=15cm and BC=(3x−1)=(3×3−1)=8cm
Now, AC
2
+AB
2
+BC
2
⇒AC
2
=15
2
+8
2
⇒AC
2
=289⇒AC=17cm
Hence, hypotenuse =17cm
Answer:
hi
Step-by-step explanation:
i am searching for that so I don't know