B. Solve each problem. Use π= 3.14
1. What is the volume of a regular cylinder whose base has radius of 5 cm and has height of 4 cm?
2. The diameter of sphere is 10 cm. Find the volume.
3. Juice is sold in aluminum cans that measure 7 inches in height and 4 inches in diameter. How many cubic inches of juice are contained in a full can?
4. The square pyramid has a volume of
297 cm3. The area of the base is 81 cm2. What is the height?
5. A glass is 10 cm deep and 8 cm wide. How much liquid can the glass hold?
6. A glass pyramid has a height of 6 inches. Its rectangular base has a length of 4 inches and a width of 2.5 inches. Find the volume of the glass.
7. A cylinder made of quartz has a volume of 5.8 cm3. If the radius is 2 cm, find the height.
8. Find the volume of a cone with a diameter of 10 meters and a height of 5.1 meters.
9. What is the volume of a sphere with a diameter of 18 ft?
10. Find the volume of a pyramid with a rectangular base measuring 6 cm by 4 cm and height 11 cm.
1. What is the volume of a regular cylinder whose base has radius of 5 cm and has height of 4 cm?
2. The diameter of sphere is 10 cm. Find the volume.
3. Juice is sold in aluminum cans that measure 7 inches in height and 4 inches in diameter. How many cubic inches of juice are contained in a full can?
4. The square pyramid has a volume of
297 cm3. The area of the base is 81 cm2. What is the height?
5. A glass is 10 cm deep and 8 cm wide. How much liquid can the glass hold?
6. A glass pyramid has a height of 6 inches. Its rectangular base has a length of 4 inches and a width of 2.5 inches. Find the volume of the glass.
7. A cylinder made of quartz has a volume of 5.8 cm3. If the radius is 2 cm, find the height.
8. Find the volume of a cone with a diameter of 10 meters and a height of 5.1 meters.
9. What is the volume of a sphere with a diameter of 18 ft?
10. Find the volume of a pyramid with a rectangular base measuring 6 cm by 4 cm and height 11 cm.
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Answer:
1. 314 cm³
2. 523.33 cm³
3. 87.92 in³
4. 11 cm=h
5. 502.4 cm³
6.
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10.
Solve.
1. V=πr² h
= 3.14( 5 cm )² (4 cm)
= 3.14(25 cm²)( 4 cm)
= 3.14(100 cm³ )
V=314 cm³
2. V=4/3πr³
=4/3(3.14) (5 cm³ )
=4/3(3.14) (125 cm³)
=4/3(392.5 cm³)
V=523.33 cm³
3. V=πr²h
=3.14 (2 in²) (7in)
=3.14(4in²) (7 in)
=3.14(28 in ³)
V=87.92 in³
4.V= ⅓bh
297 cm³ =⅓ (81 cm²)(h)
297 cm³ = 27 cm² (h)
297 cm³ ÷27 cm² = 27 cm³ (h)÷ 27cm²
11cm=h
5.V=πr²h
=3.14 (4 cm²) (10 cm)
=3.14 (16 cm²) (10 cm)
=3.14(160 cm³)
V=502.4 cm³