B. Solve and graph the quadratic inequality in one variable and write the solution set either in interval notation or listing method. Write your final answer on the space provided. (Note: Use another sheet of paper for the solutions and graphing.) 4. x² + 4x +3 0 6. r? +6r2-5 7. 6r2-5r+1>O 8. 2r2+1 ir 3-5 . 9. (21-5r+4) > 0 Rei
Answers & Comments
Answer:
4. −3<x<−1
5. y<2 or y>4
6. x≤−5 or x≥−1
7. x<1/3 or x>1/2
8. −5≤r≤ -1/2
9. r<−4 or r> 5/2
Solution
4. x2+4x+3=0
(x+1)(x+3)=0(Factor left side of equation)
x+1=0 or x+3=0(Set factors equal to 0)
x=−1 or x=−3
Check intervals in between critical points. (Test values in the intervals to see if they work.)
x<−3(Doesn't work in original inequality)
−3<x<−1(Works in original inequality)
x>−1(Doesn't work in original inequality)
5.y2−6y+8>0
Let's find the critical points of the inequality.
y2−6y+8=0
(y−2)(y−4)=0(Factor left side of equation)
y−2=0 or y−4=0(Set factors equal to 0)
y=2 or y=4
Check intervals in between critical points. (Test values in the intervals to see if they work.)
y<2(Works in original inequality)
2<y<4(Doesn't work in original inequality)
y>4(Works in original inequality)
6, x2+6x≥−5
Let's find the critical points of the inequality.
x2+6x=−5
x2+6x−(−5)=−5−(−5)(Subtract -5 from both sides)
x2+6x+5=0
(x+1)(x+5)=0(Factor left side of equation)
x+1=0 or x+5=0(Set factors equal to 0)
x=−1 or x=−5
Check intervals in between critical points. (Test values in the intervals to see if they work.)
x≤−5(Works in original inequality)
−5≤x≤−1(Doesn't work in original inequality)
x≥−1(Works in original inequality)
7. 6x2−5x+1>0
Let's find the critical points of the inequality.
6x2−5x+1=0
(3x−1)(2x−1)=0(Factor left side of equation)
3x−1=0 or 2x−1=0(Set factors equal to 0)
x=
1
3
or x=
1
2
Check intervals in between critical points. (Test values in the intervals to see if they work.)
x<
1
3
(Works in original inequality)
1
3
<x<
1
2
(Doesn't work in original inequality)
x>
1
2
(Works in original inequality)
8. 2r2+11r≤−5
Let's find the critical points of the inequality.
2r2+11r=−5
2r2+11r−(−5)=−5−(−5)(Subtract -5 from both sides)
2r2+11r+5=0
(2r+1)(r+5)=0(Factor left side of equation)
2r+1=0 or r+5=0(Set factors equal to 0)
r=
−1
2
or r=−5