shivanyaaggraw
In order to arrange the books as required we have to find the largest number that divides 336 , 240, 96 exactly so we will find HCF (336,240,96) now, 336=2×2×2×2×3×7 240=2×2×2×2×3×5 96=2×2×2×2×2×3 hence, HCF (336,240,96)=2×2×2×2×3 =>48 so, there must be 48 books in each stack.
Answers & Comments
so we will find HCF (336,240,96)
now, 336=2×2×2×2×3×7
240=2×2×2×2×3×5
96=2×2×2×2×2×3
hence, HCF (336,240,96)=2×2×2×2×3 =>48
so, there must be 48 books in each stack.
Answer:
48 bookssss.............