solve both questions.... Created by saniya63. Math

solve both questions...

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saniya63 @saniya63

September 2021 2 57 Report

solve both questions...

rohitkumargupta

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HELLO DEAR,

----------------------(1)----------------------------

$\frac{ {sin}^{ 3} \alpha - {cos}^{3} \alpha }{sin \alpha - cos \alpha } \\ \\ = \frac{(sin \alpha - cos \alpha )( {sin}^{2} \alpha + {cos}^{2} \alpha + sin \alpha cos \alpha) }{(sin \alpha - cos \alpha )} \\ \\ = 1 + sin \alpha cos \alpha$

--------------------------(2)---------------------------

(1+ tan² A) / (1+ cot² A)

=> (1+ tan² A) / (1+ 1 / tan² A)

=> (1+ tan² A) / [(tan² A+ 1)/tan² A)]

=> tan²A

I HOPE ITS HELP YOU DEAR,
THANKS

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