An object of mass 80 kg moving with velocity 2 ms hit by collides with another object of mass 20 kg moving with velocity 4 ms. Find the loss of energy assuming a perfectly inelastic collision
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1) If the masses are moving in the same direction:
Apply conservation of Linear Momentum
80 * 2 + 20 * 4 = (80+20) * v
v = 2.40 m/s
Loss of energy: 1/2 [80*2² + 20 * 4² - 100 * 2.4² ]
= 32 J
Suppose they are moving in opposite directions, then,
80* 2 - 20 * 4 = (80+20) * v
v = 0.80 m/sec
Loss in KE = 1/2 * [ 80*2² + 20 * 4² - 100 * 0.80² ]
= 288 J
Verified answer
We have loss in KE = {m1m2÷2(m1+m2)}(1-e2)(u1-u2)2Putting m1=20 kg, m2=80 kg, u1=4 m/s, u2=2 m/s, and e=0
Loss in KE = 32 joule
Answer. Loss in energy is 32 joule.