A particle of mass m moves in a circular path of radius r under the action of force which delivers it constant power p and increases its speed. The angular acceleration of particle at time (t) is proportional
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power P = force x speed in direction of force
= mass x acceleration x speed
= m(dv/dt)v
where dv/dt is linear acceleration.
power P is constant so
vdv/dt = (P/m)
(1/2)v^2 = (P/m)t.
v = rw where w is angular velocity, and r is constant, so
w^2 = (2P/mr^2)t
w = ct^1/2
where c is a constant. The angular acceleration is
dw/dt = (1/2)ct^-1/2.
Answer:
Answer is F.V >0
Explanation:
just see the uploaded photo