A particle of mass M is thrown horizontally from the top of a tower and another particle of mass 2M is thrown vertically upward. the acceleration of centre of mass is ?
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From Distance = speed x time we know that,
R=v.t
For both the cases, h= -0+gt2/2
=>t=√(2h/g)
R for the second ball = v/2.t = R/2 = 125m