the moment of inertia of a circular disc of mass M and radius R about a diameter is 1/4MR square what will be its moment of inertia about an Axis passing through its Centre perpendicular to its plane
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Gyroman
Using perpendicular axes theorem , Ix + Iy = Iz 1/4MRsquare + 1/4MRsquare = 1/2MRsqaure
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tnwramit1
This is ur ans hope it will help you in case of any doubt comment below
Answers & Comments
Ix + Iy = Iz
1/4MRsquare + 1/4MRsquare = 1/2MRsqaure