A Monkey drops a coconut hitting the ground from the top of a tree 2.057s after dropping it. If the monkey was 19.6m above the ground,what is the speed of sound in air?
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Height (h) = 19.6 m
Acceleration due to gravity (g) = 9.8 m/s2
Now,
First, we have to calculate the time which the coconut took to fall on the ground from the tree.
So now,
h = ut + 1/2 gt2
=> h = 0*t + 1/2 * 9.8 * t2
=> h = 4.9 * t2
=> t2 = h/4.9
=> t2 = 19.6/4.9
=> t2 = 4
=> t = 2 seconds
Therefore,
The coconut took 2 seconds to fall on the ground from the tree.
It means that the sound of the coconut after hitting the ground reached to the monkey in ( 2.057 - 2 ) seconds i.e. in 0.057 seconds.
Hence,
The speed of the sound in air = 19.6/ 0.057
=343.85 m/s
ANSWER:
343.85m/s
EXPLANATION:
Initial velocity (u) = 0 m/s
Height (h) = 19.6 m
Acceleration due to gravity (g) = 9.8 m/s2
Now,
First, we have to calculate the time which the coconut took to fall on the ground from the tree.
So now,
h = ut + 1/2 gt2
=> h = 0*t + 1/2 * 9.8 * t2
=> h = 4.9 * t2
=> t2 = h/4.9
=> t2 = 19.6/4.9
=> t2 = 4
=> t = 2 seconds
Therefore,
The coconut took 2 seconds to fall on the ground from the tree.
It means that the sound of the coconut after hitting the ground reached to the monkey in ( 2.057 - 2 ) seconds i.e. in 0.057 seconds.
Hence,
The speed of the sound in air = 19.6/ 0.057
=343.85 m/s
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