A bullet of mass 0.5gm is fixed towards a stationary wooden block offers resistive force 1N on the bullet, find how much distance the bullet enter into the block .
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when bullet travels inside the wood it come to the rest position so final velocity is Zero i.e. v = 0
Distance travelled in wood S = 60 cm = 0.6 m
NOW ,newtons third equation of motion is :
v2 − u2 =2asas v = 0we geta = − u22sOn substituting the values we geta = −6750 m/s2
Resistive force = mass×retardation=− 0.04×6750 =− 270 N
This is the resistance offered by the wooden block.