Answer:

answer: take away: be unique:

2x (2x + 3) (2x + 3) 2x

--------------- = ------------ = ------

3x (2x + 3) (2x + 3) 3x

i don know if this thing called "take away" and "be unique" is included in your lesson but according to my studies, this is included. if it's not, then just copy the answer, and don't copy the take away and be unique.

Step-by-step explanation:

4x² + 6x

-------------

6x² + 9x

what did i notice in the problem? in numerator (4x² + 6x), i noticed that 2•2=4, 2•3=6, so we use 2 to divide them:

4x² divided by 2 = 2x, +6x divided by 2 = +3

= 2x (2x + 3)

then, in denominator, i noticed that 3•2=6, 3•3=9, so we use 3 to divide them:

6x² divided by 3 = 2x, +9x divided by 3 = +3

= 3x (2x + 3)

answer:

2x (2x + 3)

---------------

3x (2x + 3)

(i don know if this thing called take away and be unique is included in your lesson but according to my studies, this is included) we take away numbers that numerator/at the top and denominator/at the bottom has. so we take away "2x + 3" because both numerator and denominator has it.

take away:

(2x + 3)

-----------

(2x + 3)

then the "be unique" here is the left over.

be unique:

2x

----

3x

do you want more explanation? tell me in the comments :)