Write down the decimal expansions of 7/80 and 13/125 by writing their denominators in the form of 2^m×5^n,where m,n are non negative integers.
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80=2×2×2×5×5=2³×5²
Here, decimal expansion of 80 is in the form of 2^m and 5^n. (m=3 and n=2). Therefore its decimal expansion will be terminating.
The denominator of 13/ 125 is 125.
125=5×5×5=5³
Here, decimal expansion of 125 is in the form of 2^m and 5^n. (m=0 and n=3). Therefore its decimal expansion will be terminating.
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Answer:
Step-by-step explanation:
7/80
taking prime factor of 80
7/2×2×2×2×5
=7/2^4×5^1
since denominator is in the form of 2^m×5^n.
∴it is terminating