1. f(x) = x²
• vertex :
• opening of the graph :
• vertex is a ______ point
• equation of axis of symmetry (x=h) :
• range (y≥k) :
2. f(x) = 2x² + 4x - 3
• vertex :
• opening of the graph :
• vertex is a ______ point
• equation of axis of symmetry (x=h) :
• range (y≥k) :
3. f(x) = 3x² - 6x + 4
• vertex :
• opening of the graph :
• vertex is a ______ point
• equation of axis of symmetry (x=h) :
• range (y≥k) :
Answers & Comments
Step-by-step explanation:
vertex : (-1,-2)
opening of the graph: DOWNWARD
vertex is (-1,-2) point equation of the axis of symmetry : x=-1
Domain: (−∞,∞),{x|x∈R}
range: (−∞,−2),{y|y≤−2}
Vertex (h, k):
h = -b/2a
h = -4/2(2)
h = -1
k = 2(-1)² + 4(-1) - 3
k = 2 - 4 - 3
k = -5
Vertex form:
f(x) = 2(x + 1)² - 5
Answers:
Vertex (h,k) = (-1, --5)
Opening of the graph: Upward (because a=2, where a>0)
Vertex is a minimum point (because the graph opens upward)
Equation th axis of symmetry: -b/2a (h is the axis of symmetry)
Domain: {x / x is an element of Real Numbers}
Range: {y / y ≥ - 5}