Answer:
6 = -2,3
x²-2x+3x+6
×(×-2) -3(×-2)
x=2 x=3
So, to get the zero of p(x) we know that,
p(x) = 0
p(x) = x² - 5x + 6
so,
x² - 5x + 6 = 0
now , we factorise p(x) by splitting the middle term.
x² - 2x - 3x + 6 = 0
x(x-2) - 3(x-2) = 0
(x-2)(x-3)=0
now, we get the value of x = 2 and 3.
So, 2 and 3 are the zeros of the polynomial x² - 5x + 6.
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Verified answer
Answer:
6 = -2,3
x²-2x+3x+6
×(×-2) -3(×-2)
x=2 x=3
Answer:
So, to get the zero of p(x) we know that,
p(x) = 0
p(x) = x² - 5x + 6
so,
x² - 5x + 6 = 0
now , we factorise p(x) by splitting the middle term.
x² - 2x - 3x + 6 = 0
x(x-2) - 3(x-2) = 0
so,
(x-2)(x-3)=0
now, we get the value of x = 2 and 3.
So, 2 and 3 are the zeros of the polynomial x² - 5x + 6.
hope it's helpful for you
mark me Brainliest!!