Answer:

Step-by-step explanation:

let x equal the kilos of pork.

let y equal the kilos of chicken.

you have the following constraints.

the kilos of meat must be greater than or equal to 50.

the inequality to represent that is x + y >= 50

the cost for pork is 200 per kilo and the cost for chicken is 180 per kilo.

the total cost must be less than or equal to 10,000.

the inequality to represent that is 200x + 180y <= 10000

you have additional constraints in that the number of kilos of meat can't be negative.

your constraint inequalities are:

x + y >= 50

200x + 180y <= 10000

x >= 0

y >= 0

using the desmos.com calculator, you would grpah the opposite of these inequalities.

the area of the graph that is not shaded is your region of feasibility.

any coordinate points in that area will satisfy the constraints of the problem.

to illustrate, i used the coordinate point of (12,40).

the coordinate points are in (x,y) format.

x is the number of kilos of pork.

y is the numb of kilos of chicken.

i also used the coordinate points of (0,55.556) and (50,0) to further illustrate.

the corner points of that area is where the minimum or maximum solution would lie, depending on what the objective function is.

in this case, you do not appear to have an objective function that you either want to minimize or maximize.