Your friend has 56 coins consisting of P10 coins and P5 coins. She has a total of P440.
1. If x is the number of P5 coins and y is the numbe dog P10 coins, which of the following systems of equations if formed
A. x + y =56
5x + 10y = 440
B. x + y = 56
10x + 5y = 440
C. x + y = 440
x + y = 56
D. 5x + 10y = 56
x + y = 440
1. If x is the number of P5 coins and y is the numbe dog P10 coins, which of the following systems of equations if formed
A. x + y =56
5x + 10y = 440
B. x + y = 56
10x + 5y = 440
C. x + y = 440
x + y = 56
D. 5x + 10y = 56
x + y = 440
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Answer:
B.
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