Explanation:
P=V^2/R
R=V^2/P
R1=220^2/60=80.67ohm
R2=220^2/40=1210ohm
R=(806.67×1210)/(806.67+1210)
= 484ohm
I = 220/484
= 0.45 A
Hence, the current drawn from 220V is 0.45A.
Hence, The resistance of the first lamp is high.
Hence, The lamp having less resistance will glow brighter, that is lamp 2.
Hii
Thanks for thanks ^^
btw us ans m 120x ki jagah 360x hoga
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Explanation:
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Explanation:
P=V^2/R
R=V^2/P
R1=220^2/60=80.67ohm
R2=220^2/40=1210ohm
R=(806.67×1210)/(806.67+1210)
= 484ohm
I = 220/484
= 0.45 A
Hence, the current drawn from 220V is 0.45A.
Hence, The resistance of the first lamp is high.
Hence, The lamp having less resistance will glow brighter, that is lamp 2.
Hii
Thanks for thanks ^^
btw us ans m 120x ki jagah 360x hoga