Principal P=Rs.4,000. Since the interest is compounded half-yearly the number of conversion periods in 1½years are 3. Also the rate of interest per
conversion period (6 months) is 10% × 1/2 = 5%(0.05 in decimal).
Thus the amount A_n (in Rs.) is given by
A_n = P(1+i)^n
A_3 = 4,000(1+0.05)_3
= 4,630.50
The compound interest is therefore Rs. (4,630.50−4,000)
Answer:
[tex] \\ [/tex]
Step-by-step explanation:
Given : A sum of money of Rs.4000 is lent for 1.5 years at the rate of 10 % per annum Compounded Half-yearly
[tex] \\ \\ [/tex]
To Find : Compute the Compound Interest
[tex] \\ \qquad{\rule{200pt}{2pt}} [/tex]
SolutioN :
[tex] \dag \; {\underline{\underline{\sf{ \; Formula \; Used \; :- }}}} [/tex]
Where :
[tex] \dag \; {\underline{\underline{\sf{ \; Calculating \; the \; Interest \; :- }}}} [/tex]
[tex] \; \; :\implies \; \; \tt { C.I = P \bigg\lgroup 1 + \dfrac{R}{200} \bigg\rgroup^{2n} - P } \\ \\ [/tex]
[tex] \; \; :\implies \; \; \tt { C.I = 4000 \bigg\lgroup 1 + \dfrac{10}{200} \bigg\rgroup^{2 \times 1.5} - 4000 } \\ \\ [/tex]
[tex] \; \; :\implies \; \; \tt { C.I = 4000 \bigg\lgroup 1 + \dfrac{10}{200} \bigg\rgroup^{3} - 4000 } \\ \\ [/tex]
[tex] \; \; :\implies \; \; \tt { C.I = 4000 \bigg\lgroup 1 + \cancel\dfrac{10}{200} \bigg\rgroup^{3} - 4000 } \\ \\ [/tex]
[tex] \; \; :\implies \; \; \tt { C.I = 4000 \bigg\lgroup 1 + \cancel\dfrac{5}{100} \bigg\rgroup^{3} - 4000 } \\ \\ [/tex]
[tex] \; \; :\implies \; \; \tt { C.I = 4000 \bigg\lgroup 1 +0.05 \bigg\rgroup^{3} - 4000 } \\ \\ [/tex]
[tex] \; \; :\implies \; \; \tt { C.I = 4000 \bigg\lgroup 1.05 \bigg\rgroup^{3} - 4000 } \\ \\ [/tex]
[tex] \; \; :\implies \; \; \tt { C.I = 4000 \times 1.157625 - 4000 } \\ \\ [/tex]
[tex] \; \; :\implies \; \; \tt { C.I = 4630.5 - 4000 } \\ \\ [/tex]
[tex] \; \; :\implies \; \; {\underline{\boxed{\purple{\tt { C.I = Rs. \; 630.5 }}}}} \; \bigstar \\ \\ [/tex]
❛❛ Compound Interest is Rs 630.5 ! ❜❜
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Verified answer
Principal P=Rs.4,000. Since the interest is compounded half-yearly the number of conversion periods in 1½years are 3. Also the rate of interest per
conversion period (6 months) is 10% × 1/2 = 5%(0.05 in decimal).
Thus the amount A_n (in Rs.) is given by
A_n = P(1+i)^n
A_3 = 4,000(1+0.05)_3
= 4,630.50
The compound interest is therefore Rs. (4,630.50−4,000)
Answer:
[tex] \\ [/tex]
Step-by-step explanation:
Given : A sum of money of Rs.4000 is lent for 1.5 years at the rate of 10 % per annum Compounded Half-yearly
[tex] \\ \\ [/tex]
To Find : Compute the Compound Interest
[tex] \\ \qquad{\rule{200pt}{2pt}} [/tex]
SolutioN :
[tex] \dag \; {\underline{\underline{\sf{ \; Formula \; Used \; :- }}}} [/tex]
[tex] \\ [/tex]
Where :
[tex] \\ \\ [/tex]
[tex] \dag \; {\underline{\underline{\sf{ \; Calculating \; the \; Interest \; :- }}}} [/tex]
[tex] \; \; :\implies \; \; \tt { C.I = P \bigg\lgroup 1 + \dfrac{R}{200} \bigg\rgroup^{2n} - P } \\ \\ [/tex]
[tex] \; \; :\implies \; \; \tt { C.I = 4000 \bigg\lgroup 1 + \dfrac{10}{200} \bigg\rgroup^{2 \times 1.5} - 4000 } \\ \\ [/tex]
[tex] \; \; :\implies \; \; \tt { C.I = 4000 \bigg\lgroup 1 + \dfrac{10}{200} \bigg\rgroup^{3} - 4000 } \\ \\ [/tex]
[tex] \; \; :\implies \; \; \tt { C.I = 4000 \bigg\lgroup 1 + \cancel\dfrac{10}{200} \bigg\rgroup^{3} - 4000 } \\ \\ [/tex]
[tex] \; \; :\implies \; \; \tt { C.I = 4000 \bigg\lgroup 1 + \cancel\dfrac{5}{100} \bigg\rgroup^{3} - 4000 } \\ \\ [/tex]
[tex] \; \; :\implies \; \; \tt { C.I = 4000 \bigg\lgroup 1 +0.05 \bigg\rgroup^{3} - 4000 } \\ \\ [/tex]
[tex] \; \; :\implies \; \; \tt { C.I = 4000 \bigg\lgroup 1.05 \bigg\rgroup^{3} - 4000 } \\ \\ [/tex]
[tex] \; \; :\implies \; \; \tt { C.I = 4000 \times 1.157625 - 4000 } \\ \\ [/tex]
[tex] \; \; :\implies \; \; \tt { C.I = 4630.5 - 4000 } \\ \\ [/tex]
[tex] \; \; :\implies \; \; {\underline{\boxed{\purple{\tt { C.I = Rs. \; 630.5 }}}}} \; \bigstar \\ \\ [/tex]
[tex] \\ \\ [/tex]
❛❛ Compound Interest is Rs 630.5 ! ❜❜
[tex] \\ \qquad{\rule{200pt}{2pt}} [/tex]