vertex is (8,3). Axis of symmetry is x=8. x intercepts are
8
±
√
3
2
. y intercept is (0, -253). Domain
{
x
:
x
∈
R
,
−
∞
≤
x
≤
+
∞
}
. Range is
{
y
:
y
∈
R
,
3
≥
y
≥
−
∞
}
Explanation:
The given equation is already given in vertex form. The figure is an vertical parabola, opening down ward. The vertex is (8,3), axis of symmetry is x-8=0 that is x=8. In the given equation put, x=0 to obtain y= -253. Hence y- intercept is (0, -253). For x intercepts put f(x)=0 and solve for x to get x=
8
±
√
3
2
domain is whole of real numbers as x can have any real value.
Answers & Comments
Answer:
vertex is (8,3). Axis of symmetry is x=8. x intercepts are
8
±
√
3
2
. y intercept is (0, -253). Domain
{
x
:
x
∈
R
,
−
∞
≤
x
≤
+
∞
}
. Range is
{
y
:
y
∈
R
,
3
≥
y
≥
−
∞
}
Explanation:
The given equation is already given in vertex form. The figure is an vertical parabola, opening down ward. The vertex is (8,3), axis of symmetry is x-8=0 that is x=8. In the given equation put, x=0 to obtain y= -253. Hence y- intercept is (0, -253). For x intercepts put f(x)=0 and solve for x to get x=
8
±
√
3
2
domain is whole of real numbers as x can have any real value.
Domain
{
x
:
x
∈
R
,
−
∞
≤
x
≤
+
∞
}
. Range is
{
y
:
y
∈
R
,
3
≥
y
≥
−
∞
}