pano po ba gagawin dyan?
Answer:
x²+ x – 12
Step-by-step explanation:
OverviewSimplify
QUESTION
(x+4)(x-3)(x+4)(x−3)
STEPS TO SOLVE
1
Distribute
{\color{#c92786}{(x+4)(x-3)}}(x+4)(x−3)
{\color{#c92786}{x(x-3)+4(x-3)}}x(x−3)+4(x−3)
2
{\color{#c92786}{x(x-3)}}+4(x-3)x(x−3)+4(x−3)
{\color{#c92786}{x^{2}-3x}}+4(x-3)x2−3x+4(x−3)
3
x^{2}-3x2−3x+4(x−3)
x^{2}-3x+{\color{#c92786}{4x-12}}x2−3x+4x−12
4
x^{2}+{\color{#c92786}{1x}}-12x2+1x−12
5
Multiply by 1
x^{2}+1x-12x2+1x−12
x^{2}+x-12x2+x−12
SOLUTION
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Answers & Comments
pano po ba gagawin dyan?
Answer:
x²+ x – 12
Step-by-step explanation:
OverviewSimplify
QUESTION
(x+4)(x-3)(x+4)(x−3)
STEPS TO SOLVE
1
Distribute
{\color{#c92786}{(x+4)(x-3)}}(x+4)(x−3)
{\color{#c92786}{x(x-3)+4(x-3)}}x(x−3)+4(x−3)
2
Distribute
{\color{#c92786}{x(x-3)}}+4(x-3)x(x−3)+4(x−3)
{\color{#c92786}{x^{2}-3x}}+4(x-3)x2−3x+4(x−3)
3
Distribute
x^{2}-3x2−3x+4(x−3)
x^{2}-3x+{\color{#c92786}{4x-12}}x2−3x+4x−12
4
x^{2}+{\color{#c92786}{1x}}-12x2+1x−12
5
Multiply by 1
x^{2}+1x-12x2+1x−12
x^{2}+x-12x2+x−12
SOLUTION
x^{2}+x-12x2+x−12