x^2+y^2-4x-6y-12=0 in this circle find center and radius
Answers & Comments
RivenDost
Given eq. is x^2+y^2-4x-6y-12=0 x^2+y^2-4x-6y=12 Completing the squares within the parenthesis we get x^2-4x+4+y^-6y+9=12+4+9 (x-2)^2+(y-3)^2=25 or (5)^2 Comparing given with the general eq. of the circle (x-h)^2+(y-k)^2=r^2 we have h=2, k=3 and r=5 so center of the circle=(2,3) and radius of the circle is 5 hope it helps...
Answers & Comments
x^2+y^2-4x-6y-12=0
x^2+y^2-4x-6y=12
Completing the squares within the parenthesis we get
x^2-4x+4+y^-6y+9=12+4+9
(x-2)^2+(y-3)^2=25 or (5)^2
Comparing given with the general eq. of the circle
(x-h)^2+(y-k)^2=r^2
we have
h=2, k=3 and r=5
so center of the circle=(2,3) and radius of the circle is 5
hope it helps...