Factorization.
⇒ x² - 12x + 27 = 0.
Factorize the equation into middle term splits, we get.
⇒ x² - 9x - 3x + 27 = 0.
⇒ x(x - 9) - 3(x - 9) = 0.
⇒ (x - 3)(x - 9) = 0.
⇒ x = 3 and x = 9.
Nature of the roots of quadratic expression.
(1) Roots are real and unequal, if b² - 4ac > 0.
(2) Roots are rational and different, if b² - 4ac is a perfect square.
(3) Roots are real and equal, if b² - 4ac = 0.
(4) If D < 0 Roots are imaginary and unequal Or complex conjugate.
Step-by-step explanation:
x2-12x+27=0
x2 -(9+3)x +27 [•split 12 in 9 and 3]
x2 -9x-3x +27 =0
x(x-9) -3(x-9)=0
(x-9) (x-3) =0
x-9=0, x-3=0
[x=9] , [x=3] answer
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Answers & Comments
EXPLANATION.
Factorization.
⇒ x² - 12x + 27 = 0.
Factorize the equation into middle term splits, we get.
⇒ x² - 9x - 3x + 27 = 0.
⇒ x(x - 9) - 3(x - 9) = 0.
⇒ (x - 3)(x - 9) = 0.
⇒ x = 3 and x = 9.
MORE INFORMATION.
Nature of the roots of quadratic expression.
(1) Roots are real and unequal, if b² - 4ac > 0.
(2) Roots are rational and different, if b² - 4ac is a perfect square.
(3) Roots are real and equal, if b² - 4ac = 0.
(4) If D < 0 Roots are imaginary and unequal Or complex conjugate.
Verified answer
Step-by-step explanation:
x2-12x+27=0
x2 -(9+3)x +27 [•split 12 in 9 and 3]
x2 -9x-3x +27 =0
x(x-9) -3(x-9)=0
(x-9) (x-3) =0
x-9=0, x-3=0
[x=9] , [x=3] answer
I am new so pls mark me as brainliest