Answer:
[tex]\sf x^2+169=0[/tex]
[tex]\sf \sqrt{x^2} = \sqrt{169}[/tex]
x = ±13
#CarryOnLearning
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Verified answer
Answer:
[tex]\sf x^2+169=0[/tex]
[tex]\sf \sqrt{x^2} = \sqrt{169}[/tex]
x = ±13
#CarryOnLearning