Answer:
[tex]x^2 + y^2 = 98[/tex] [Ans]
Step-by-step explanation:
We know,
[tex]x^2 + \frac{1}{x^2} = (x - \frac{1}{x} )^2 +2[/tex] ..................................(i)
Given, x= 5 + 2√6
Then,
[tex]\frac{1}{x } = \frac{1}{5+2\sqrt6} = \frac{5-2\sqrt6}{(5)^2 -(2\sqrt6)^2} = \frac{5-2\sqrt6}{25-24}[/tex]
[tex]= 5- 2\sqrt6[/tex]
∴ [tex]x^{2} + y^{2} = x^2 + \frac{1}{x^2} =(5 + 2 \sqrt6)^2 + (5-2\sqrt6)^2[/tex]
[tex]= (5+ 2\sqrt6-5 + 2\sqrt6)^2 +2[/tex] [Using equation (i)]
[tex]= (4\sqrt6)^2 + 2[/tex]
= 96 + 2
= 98 [Ans]
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Answers & Comments
Answer:
[tex]x^2 + y^2 = 98[/tex] [Ans]
Step-by-step explanation:
We know,
[tex]x^2 + \frac{1}{x^2} = (x - \frac{1}{x} )^2 +2[/tex] ..................................(i)
Given, x= 5 + 2√6
Then,
[tex]\frac{1}{x } = \frac{1}{5+2\sqrt6} = \frac{5-2\sqrt6}{(5)^2 -(2\sqrt6)^2} = \frac{5-2\sqrt6}{25-24}[/tex]
[tex]= 5- 2\sqrt6[/tex]
∴ [tex]x^{2} + y^{2} = x^2 + \frac{1}{x^2} =(5 + 2 \sqrt6)^2 + (5-2\sqrt6)^2[/tex]
[tex]= (5+ 2\sqrt6-5 + 2\sqrt6)^2 +2[/tex] [Using equation (i)]
[tex]= (4\sqrt6)^2 + 2[/tex]
= 96 + 2
= 98 [Ans]