Answer:
[tex]\huge\rm{\color{purple}{{\underline{༊Ꭿᥒ}}}} {\color{orchid}{{\underline{᥉ᥕ}}}}{\pink{{\underline{ᥱꭱ༊}}}} {\color{lightpink}{}}[/tex]
Step-by-step explanation:
To evaluate the given double integral, we can start by integrating with respect to y first and then with respect to x.
First, we integrate with respect to y:
∫(0 to 2/x) e^(xy) dy
Using the power rule for integration, we can integrate e^(xy) with respect to y:
= [1/x * e^(xy)] evaluated from 0 to 2/x
= (1/x * e^(2)) - (1/x * e^(0))
= (1/x * e^(2)) - (1/x * 1)
= (e^(2) - 1)/x
Now, we need to integrate this result with respect to x:
∫(1 to 2) (e^(2) - 1)/x dx
Using the power rule for integration, we can integrate (e^(2) - 1)/x with respect to x:
= [(e^(2) - 1) * ln|x|] evaluated from 1 to 2
= [(e^(2) - 1) * ln|2|] - [(e^(2) - 1) * ln|1|]
= (e^(2) - 1) * ln(2) - (e^(2) - 1) * ln(1)
= (e^(2) - 1) * ln(2)
Therefore, the value of the given integral is (e^(2) - 1) * ln(2).
To reverse the order of integration, we need to rewrite the integral with the limits swapped and change the order of integration:
∫(1 to 2) ∫(0 to 2/x) e^(xy) dy dx
= ∫(0 to 2) ∫(1 to 2/x) e^(xy) dx dy
Now, we can evaluate this reversed integral using the same steps as before.
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Your standard
the answer
\bold{ \red{Please} \: \blue{\: Follow} \: \pink{ \: Me} \: \green{\: ♡}}PleaseFollowMe♡ .............\bold{ \red{Drop} \: \blue{\: some} \: \pink{ \: thanks } \: \green{\: ♡}}Dropsomethanks♡ .............\bold{ \red{Please} \: \blue{\: Follow} \: \pink{ \: Me} \: \green{\: ♡}}PleaseFollowMe♡ .............\bold{ \red{Drop} \: \blue{\: some} \: \pink{ \: thanks } \: \green{\: ♡}}Dropsomethanks♡ .............
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Answer:
[tex]\huge\rm{\color{purple}{{\underline{༊Ꭿᥒ}}}} {\color{orchid}{{\underline{᥉ᥕ}}}}{\pink{{\underline{ᥱꭱ༊}}}} {\color{lightpink}{}}[/tex]
Step-by-step explanation:
To evaluate the given double integral, we can start by integrating with respect to y first and then with respect to x.
First, we integrate with respect to y:
∫(0 to 2/x) e^(xy) dy
Using the power rule for integration, we can integrate e^(xy) with respect to y:
= [1/x * e^(xy)] evaluated from 0 to 2/x
= (1/x * e^(2)) - (1/x * e^(0))
= (1/x * e^(2)) - (1/x * 1)
= (e^(2) - 1)/x
Now, we need to integrate this result with respect to x:
∫(1 to 2) (e^(2) - 1)/x dx
Using the power rule for integration, we can integrate (e^(2) - 1)/x with respect to x:
= [(e^(2) - 1) * ln|x|] evaluated from 1 to 2
= [(e^(2) - 1) * ln|2|] - [(e^(2) - 1) * ln|1|]
= (e^(2) - 1) * ln(2) - (e^(2) - 1) * ln(1)
= (e^(2) - 1) * ln(2)
Therefore, the value of the given integral is (e^(2) - 1) * ln(2).
To reverse the order of integration, we need to rewrite the integral with the limits swapped and change the order of integration:
∫(1 to 2) ∫(0 to 2/x) e^(xy) dy dx
= ∫(0 to 2) ∫(1 to 2/x) e^(xy) dx dy
Now, we can evaluate this reversed integral using the same steps as before.
[tex]\bold{ \red{Please} \: \blue{\: Follow} \: \pink{ \: Me} \: \green{\: ♡}}[/tex].............[tex]\bold{ \red{Drop} \: \blue{\: some} \: \pink{ \: thanks } \: \green{\: ♡}}[/tex].............[tex]\bold{ \red{Please} \: \blue{\: Follow} \: \pink{ \: Me} \: \green{\: ♡}}[/tex].............[tex]\bold{ \red{Drop} \: \blue{\: some} \: \pink{ \: thanks } \: \green{\: ♡}}[/tex].............
Your standard
Answer:
the answer
Step-by-step explanation:
To evaluate the given double integral, we can start by integrating with respect to y first and then with respect to x.
First, we integrate with respect to y:
∫(0 to 2/x) e^(xy) dy
Using the power rule for integration, we can integrate e^(xy) with respect to y:
= [1/x * e^(xy)] evaluated from 0 to 2/x
= (1/x * e^(2)) - (1/x * e^(0))
= (1/x * e^(2)) - (1/x * 1)
= (e^(2) - 1)/x
Now, we need to integrate this result with respect to x:
∫(1 to 2) (e^(2) - 1)/x dx
Using the power rule for integration, we can integrate (e^(2) - 1)/x with respect to x:
= [(e^(2) - 1) * ln|x|] evaluated from 1 to 2
= [(e^(2) - 1) * ln|2|] - [(e^(2) - 1) * ln|1|]
= (e^(2) - 1) * ln(2) - (e^(2) - 1) * ln(1)
= (e^(2) - 1) * ln(2)
Therefore, the value of the given integral is (e^(2) - 1) * ln(2).
To reverse the order of integration, we need to rewrite the integral with the limits swapped and change the order of integration:
∫(1 to 2) ∫(0 to 2/x) e^(xy) dy dx
= ∫(0 to 2) ∫(1 to 2/x) e^(xy) dx dy
Now, we can evaluate this reversed integral using the same steps as before.
\bold{ \red{Please} \: \blue{\: Follow} \: \pink{ \: Me} \: \green{\: ♡}}PleaseFollowMe♡ .............\bold{ \red{Drop} \: \blue{\: some} \: \pink{ \: thanks } \: \green{\: ♡}}Dropsomethanks♡ .............\bold{ \red{Please} \: \blue{\: Follow} \: \pink{ \: Me} \: \green{\: ♡}}PleaseFollowMe♡ .............\bold{ \red{Drop} \: \blue{\: some} \: \pink{ \: thanks } \: \green{\: ♡}}Dropsomethanks♡ .............
Your standard