Verified answer

Step-by-step explanation:

on putting x= 1 make eq 0

so x-1 is a factor

x⁴- 6x³+ 8x²+ 3x- 6

x⁴-x³-5x³+5x²+3x²-3x+6x-6

x³(x-1)-5x²(x-1)+3x(x-1)+6(x-1)

(x-1)(x³-5x²+3x+6)

x= 2 make eq. (x³-5x²+3x+6) =0

so,

x-2 be a factor

(x-1)(x³-5x²+3x+6)

(x-1)(x³-2x²-3x²+6x-3x+6)

(x-1){x²(x-2)-3x(x-2)-3(x-2)}

(x-1)(x-2)(x²-3x-3)

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